A soccer ball is kicked horizontally at 15.8 m/s off the top of a field house and lands 33.9 meters from the base of the field house. Determine the height of the field house

Respuesta :

First figure out the time by using the equation (you know v and x):
 [tex] v_{x} = \frac{x}{t} [/tex] 

Then, use the following equation to figure out what y (height of the field house is):
[tex]y= v_{y} t+ \frac{1}{2}at^{2} [/tex]

Remember that you can always analyze half of the scenario by dividing the time in half, and setting vy = 0 if at all it helps.