tuscany44
tuscany44 tuscany44
  • 09-06-2014
  • Mathematics
contestada

Can anyone help me with this one?

0 < 2 - 3 x < 4

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crisforp
crisforp crisforp
  • 09-06-2014
0 < 2 - 3 x < 4  
-2 ≤ - 3x ≤ 2
2 ≥ 3x ≥ -2
2/3 ≥ x ≥ -2/3
x∈[ - 2 / 3 ,  + 2 / 3 ]
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konrad509
konrad509 konrad509
  • 09-06-2014
[tex]0 \leq 2 - 3 x \leq 4\\ -2\leq-3x\leq2\\ \frac{2}{3}\geq x\geq-\frac{2}{3}\\ x\in\langle-\frac{2}{3},\frac{2}{3}\rangle [/tex]
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