we know that
a) [tex] \frac{1}{10} [/tex] of an hour is equal to
convert to minutes
[tex] \frac{1}{10} * 60 =6\ minutes [/tex]
b) [tex] \frac{1}{12} [/tex] of an hour is equal to
convert to minutes
[tex] \frac{1}{12} * 60 =5\ minutes [/tex]
therefore
[tex] \frac{1}{12} [/tex] is faster than [tex] \frac{1}{10} [/tex]
the answer is
On the second attempt Ely is more faster
Alternative Method
we know that
When comparing two fractions that have the same numerator, the smallest of the two fractions will be the one with the highest denominator.
the fraction [tex] \frac{1}{12} [/tex]
has the highest denominator
so
[tex] \frac{1}{12} [/tex] is the smallest of the two fractions
therefore
the answer is
On the second attempt Ely is more faster
