When the fraction [tex]\frac{3}{5}[/tex] divided by [tex]\frac{4}{7}[/tex] divided by [tex]\frac{9}{10}[/tex] is [tex]1\frac{1}{6}[/tex]
Given that,
- The fractions are [tex]\frac{3}{5}, \frac{4}{7}, and \frac{9}{10}[/tex]
First, we divide the first two fractions i.e.
[tex]= \frac{3}{5} \times \frac{7}{4} \\\\= \frac{21}{20}[/tex]
Now multiply the given fraction with the third one by reciprocal it.
[tex]= \frac{21}{20} \times \frac{10}{9} \\\\= \frac{210}{180} \\\\= \frac{7}{6}\\\\[/tex]
[tex]= 1\frac{1}{6}[/tex]
Therefore we can conclude that when the fraction [tex]\frac{3}{5}[/tex] divided by [tex]\frac{4}{7}[/tex] divided by [tex]\frac{9}{10}[/tex] is [tex]1\frac{1}{6}[/tex]
Learn more: brainly.com/question/6201432
