Answer:
[tex]\text{The solution is } x=\frac{5\pm \sqrt{41}}{4}[/tex]
Step-by-step explanation:
Given quadratic equation
[tex] 2x^2-5x-2=0[/tex]
we have to solve the above equation for x.
[tex]2x^2-5x-2=0\\\\\text{Comparing above equation with standard quadratic equation }\\ax^2+bx+c=0\text{, we get}\\\\a=2, b=-5, c=-2\\\\\text{The solution is }\\\\x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}\\\\x=\frac{-(-5)\pm \sqrt{25-4(2)(-2)}}{2(2)}\\\\x=\frac{5\pm \sqrt{25+16}}{4}\\\\x=\frac{5\pm \sqrt{41}}{4}\\\\\text{The solution is } x=\frac{5\pm \sqrt{41}}{4}[/tex]
