Respuesta :
School A: 15/35 * 100 = 42.8%
School B: 13/42 * 100 = 30.9%
School C: 8/21 * 100 = 38.1%
School D: 16/41 * 100 = 39.2%
Therefore school A has the greatest percentage of students who like burgers for lunch.
School B: 13/42 * 100 = 30.9%
School C: 8/21 * 100 = 38.1%
School D: 16/41 * 100 = 39.2%
Therefore school A has the greatest percentage of students who like burgers for lunch.
Answer:
School A has the greatest percentage of students who like burgers for lunch i.e 42.86%.
Step-by-step explanation:
Consider the provided table.
Total Number of Students Who Liked Burgers
in the Cafeteria
School A 35 15
School B 42 13
School C 21 8
School D 41 16
Now calculate the percentage of students who like burgers for lunch as shown:
For School A: 15 student liked burger out of 35.
[tex] \frac{15}{35}\times 100=42.86\%[/tex]
For School B: 13 student liked burger out of 42.
[tex] \frac{13}{42}\times 100=30.95\%[/tex]
For School C: 8 student liked burger out of 21.
[tex] \frac{8}{21}\times 100=38.095\%[/tex]
For School D: 16 student liked burger out of 41.
[tex] \frac{16}{41}\times 100=39.024\%[/tex]
From the above calculation it is clear that School A has the greatest percentage of students who like burgers for lunch i.e 42.86%.