contestada

A bobsleigh with four people on board has a total mass of 610 kg. How fast is the sleigh moving if it has a kinetic energy of 40.0 kJ?

Respuesta :

40 kj to j is 40000 j, we know that KE=(1/2)mv², therefore v=√2K/m, therefore v=√2×40000j/610kg, v=11.5 m/s
davidlcastiblanco

Answer:

v= 11.45 [tex]\frac{m}{s}[/tex]

Explanation:

kinetic equation

[tex]E_{k} = \frac{1}{2} * m * v^{2}[/tex], [tex]E_{k} = 40.0 k J [/tex] , [tex]m=610 kg [/tex]

[tex]E_{k}*2 = m * v^{2}\\\frac{2*E_{k}}{m} = v^{2} \\v =  \sqrt{\frac{2*E_{k}}{m} } \\v =  \sqrt{\frac{2*40x10^{3} \frac{kg*m^{2} }{s^{2}}  }{610 kg} } = \sqrt{131.147 \frac{m^{2}}{s^{2}} } \\[/tex]

[tex]v= 11.45 \frac{m}{s}[/tex]

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