Let T be the number of teams after n rounds.
[tex]T=128\times(\frac{1}{2})^{n}[/tex]
When T = 16, we get:[tex]16=128\times(\frac{1}{2})^{n}[/tex]
Dividing both sides by 128, we get:
[tex]\frac{1}{8}=(\frac{1}{2})^{n}[/tex]
Therefore n = 3
The answer is 'after the third round'.
