contestada

A boater travels 33 miles per hour on the water on a still day. During one particular windy day, he finds that he travels 28 miles with the wind behind him in the same amount of time that he travels 14 miles into the wind. Find the rate of the wind.

Respuesta :

Knownothing
W = speed of wind (33 + W = speed with) (33-W = speed against) 28/(33+w)=14/(33-w), cross multiply 14/(33+w)=28/(33-w), 462+14w=924-28w, 42w=462, w=11

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