Assuming : k=weight of kingfish, a=weight of amberjack, m=weight of white marlin, t=weight of tarpon
The sum of all four fish is 252, so k+a+m+t=252
the kingfish weighs twice as much as the amberjack, so 2a=k.
the marlin weighs twice as much as the kingfish, so 2k=m.
the tarpon weighs 5 times as much as the amberjack, so 5a=t.
Replace the terms k, m, and t: 2a+a+2k+5a=252. k=2a so 2a+a+2(2a)+5a=252. Combine like terms: 8a+4a=252, 12a=252. Divide both sides by 12: a=21. The amberjack weighs 21 pounds. From this, figure out the rest: k=2a=2(21)=42, m=2k=4a=4(21)=42, t=5(21)=105.
Concluding answer - The weights are: amberjack, 21 lbs; kingfish, 42 lbs; white marlin, 84 lbs; tarpon, 105 lbs.
