we know that
Area of the square=[tex] x^{2} [/tex]
where
x is the length side of the square
in this problem
[tex] x=3^{\frac{2}{7}} [/tex] in
so
[tex] Area=(3^{\frac{2}{7}})^{2} \\ Area=3^{\frac{(2*2)}{7}} \\ Area=3^{\frac{4}{7}} [/tex]in²
therefore
the answer is the option
three to the power of four sevenths square inches
