Respuesta :
pH= (-log[H+ concentration])
The tank currently has a pH=7.0.
7.0= -log[H+]
10^-7= [H+]
[H+]= 0.0000001 moles of H+ per a Liter
The tank needs a pH of 5.0
10^-5.0= [H+]
[H+]= 0.00001 moles of H+ per a Liter
(0.00001)/(0.0000001)= 100
Answer: Therefore, the tank needs have an H+ concentration 100 times greater than its current concentration to reach a pH of 5.0.
The tank currently has a pH=7.0.
7.0= -log[H+]
10^-7= [H+]
[H+]= 0.0000001 moles of H+ per a Liter
The tank needs a pH of 5.0
10^-5.0= [H+]
[H+]= 0.00001 moles of H+ per a Liter
(0.00001)/(0.0000001)= 100
Answer: Therefore, the tank needs have an H+ concentration 100 times greater than its current concentration to reach a pH of 5.0.
A higher pH is less acidic than a lower pH.
pH = log { 1 / [H3O+] },where [H3O+] is the same that [H+].
Then, you need to decrease the pH of the solution from 7.0 to 5.0, which means you have to make it more acidic which is the same that increase the concentration of H+.
pH = 7.0 = log { 1/ [H3O+] } => [H3O+] = 10^-7M
pH = 5.0 = log { 1 / [H3O+] } => [H3O+]= 10^ - 5M
So, the answer is that to correct the pH, the concentration of hydrogen ionshall be increased from 10 ^ - 7 M to 10 ^ - 5M.
pH = log { 1 / [H3O+] },where [H3O+] is the same that [H+].
Then, you need to decrease the pH of the solution from 7.0 to 5.0, which means you have to make it more acidic which is the same that increase the concentration of H+.
pH = 7.0 = log { 1/ [H3O+] } => [H3O+] = 10^-7M
pH = 5.0 = log { 1 / [H3O+] } => [H3O+]= 10^ - 5M
So, the answer is that to correct the pH, the concentration of hydrogen ionshall be increased from 10 ^ - 7 M to 10 ^ - 5M.