At an assembly 7 out of the first 10 students who entered the gym were carrying a backpack. Based on this information, if 700 students were at the assembly, how many students could be expected to be carrying a backpack?

7 out of 10 were carrying a backpack...and 3 out of 10 were not
that means 7/10 of the total students had backpacks and 3/10 of the total students did not

7/10 * 700 = 4900/10 = 490 had backpacks <==
3/10 * 700 = 2100/10 = 210 did not

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keshavgandhi04 keshavgandhi04 · Answer 2 · 2021-12-27T15:01:49+01:00

The total number of students expected to be carrying a backpack is 490 and this can be determined by using the unitary method.

Given :

At an assembly 7 out of the first 10 students who entered the gym were carrying a backpack.
700 students were at the assembly.

The following steps can be used in order to determine the total number of students expected to be carrying a backpack:

Step 1 - The unitary method can be used in order to determine the total number of students expected to be carrying a backpack.

Step 2 - According to the given data, at an assembly 7 out of the first 10 students who entered the gym were carrying a backpack.

Step 3 - Let the total number of students expected to be carrying a backpack be 'x'.

Step 4 - So, the value of 'x' is calculated as:

[tex]x = \dfrac{700}{10}\times 7[/tex]

[tex]x = 490\;{\rm students}[/tex]

The total number of students expected to be carrying a backpack is 490.

For more information, refer to the link given below:

https://brainly.com/question/12116123