Respuesta :
7√27 + 5√48 in simple radical form
41 sqrt(3)
√27 can be written as √(3*3^2) = 3√3
√48 can be written as √(3*4^2) = 4√3
so 7√27 + 5√48 = 7*3√3 + 5*4√3 = 21√3 + 20√3 = 41√3
Answer: 41√3 will be the simplified radical form of given expression.
Explanation:
Since, Given expression is 7√27+5√48
= 7×√9×√3+ 5 × √16×√3 (because, √(m×n)=√m×√n)
= 7×3×√3+5 × 4×√3 ( because, √9=3 and √16=4)
= 21√3+20√3 (because m×√n=m√n)
= (21+20)√3 ( by associative property under multiplication over addition)
=41√3. (by addition)
⇒7√27+5√48=41√3
Thus, the simplified form of 7√27+5√48 is 41√3.
