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The system of equations is graphed on the coordinate plane. y=−x−2y=3x+2 A graph with a blue line passing through coordinates (-2, 0), (-1, -1) and (0, -2) and a red line passing through coordinates (-1, -1) and (-.75, 0). Enter the coordinates of the solution to the system of equations in the boxes. ( −1, ​ −1​ )

Respuesta :

y=-x-2
y=3x+2
multiply the first equation by 3: 3y=-3x-6
add up this equation with equation 2: 4y=-4, y=-1
-1=3x+2, x=-1
so the solution point is (-1,-1)
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ANSWER

The solution is

[tex](-1,-1)[/tex]
EXPLANATION

The given system of equations are

[tex]y = - x - 2[/tex]
[tex]y = 3x + 2[/tex]

The graph of the first equation is the blue line and the graph of the second equation is the red line in graph in the attachment.

The coordinates of the point of intersection to the system is

[tex](-1,-1)[/tex]
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