Respuesta :

 S = 2πRh + 2πR2 

S -2πR2= 2πRh 

(S -2πR2) / (2πR) = h

[tex]S=2\pi r^2+2\pi rh[/tex]

We need to solve for h. It means we need to get 'h' alone

First we subtract [tex] 2\pi r^2[/tex] on both sides

[tex]S - 2\pi r^2=2\pi r^2- 2\pi r^2+2\pi rh[/tex]

[tex]S - 2\pi r^2=2\pi rh[/tex]

Now we divide by  [tex]2\pi r[/tex] on both sides

[tex]\frac{S - 2\pi r^2}{2\pi r} = \frac{2\pi rh}{2\pi r}[/tex]

[tex]\frac{S - 2\pi r^2}{2\pi r} =h[/tex]

We got h alone. Solved for h

[tex]h=\frac{S - 2\pi r^2}{2\pi r}[/tex]