Δ PQR and Δ STU based on the diagrams are congruent triangles which means that each corresponding side of the triangle are equal.
⇒ PR = SU
∴ 3y - 2 = y + 4
3y - y = 4 + 2
2y = 6
y = 3
Now, the perimeter of ΔPQR = 4 + (3y - 2) + 6 ft
since y = 3
then the perimeter of ΔPQR = 4 + (3(3) - 2) + 6 ft
the perimeter of ΔPQR = 17 ft
