Respuesta :
[tex]\bf _nP_r=\cfrac{n!}{(n-r)!}\qquad \qquad \qquad _6P_2=\cfrac{6!}{(6-2)!}[/tex]
Answer:
[tex]P(6,2)=30[/tex]
Step-by-step explanation:
We are asked to evaluate the permutation [tex]_{2}^{6}\textrm{P}[/tex].
We will use permutations formula to solve our given problem.
[tex]P(n,r)=\frac{n!}{(n-r)!}[/tex], where,
n = Total number of items,
r = Number of items taken at a time.
Upon substituting our given values we will get,
[tex]P(6,2)=\frac{6!}{(6-2)!}[/tex]
[tex]P(6,2)=\frac{6!}{4!}[/tex]
[tex]P(6,2)=\frac{6*5*4!}{4!}[/tex]
[tex]P(6,2)=6*5[/tex]
[tex]P(6,2)=30[/tex]
Therefore, the answer would be 30.
