1. At STP, how many liters of oxygen are required to react completely with 3.6 liters of hydrogen to form water? 2H2(g)+O2(g) -> 2H2O(g)

a. 1.8 L
b. 3.6 L
c. 2.0 L
d. 2.4 L

2. Which conversion factor do you use first to calculate the number of grams of CO2 produced by the reaction of 50.6 g of CH4 with O2? The equation for the complete combustion of methane is: CH4(g) +2O2(g) -> CO2 + 2H2O(l)

a. 1 mol CH4/ 16.0g CH4
b. 2 mol O2/1 mol CO2
c. 16.0g CH4/1 mol CO4
d. 44.0g CO2/2 mol CO2

3. Which of the following statements is true about the following reaction? 3NaHCO3(aq) + C6H8)7(aq) -> 3CO2(g) + 3H2O(s) + Na3C6H5O7(aq)

a. 22.4 L of CO2(g) are produced for every liter of C6H8O7(aq) reacted.
b. 1 mole of water is produced for every mole of carbon dioxide produced.
c. 6.02 x 10^23 molecules of Na3C6H5O7(aq) are produced for every mole of NaHCO3(aq) used.
d. 54 g of water are produced for every mole of NaHC)3(aq) produced.

Respuesta :

SASSAS
1. is a
2.is a
3.is b
hope this helps

Stoichiometry provides a way of calculating the amount of substance produced in a reaction.

The reaction equation is;

2H2(g)+O2(g) -> 2H2O(g)

We know that 1 mole of a gas occupies 22.4 L

If 22.4 L of oxygen reacts with 44.8 L of hydrogen

x L of oxygen reacts with 3.6 L of hydrogen

x =  22.4 L ×3.6 L/44.8 L

x = 1.8 L

The first conversion factor when calculating the number of grams of CO2 produced from reaction of 50.6 g of CH4 with O2 is 1 mol CH4/ 16.0g CH4.

Given the reaction; 3NaHCO3(aq) + C6H8)7(aq) -> 3CO2(g) + 3H2O(s) + Na3C6H5O7(aq), the true statement is; 1 mole of water is produced for every mole of carbon dioxide produced.

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