Hi there!
The question here gives us an inequality, and it tells us to solve for x.
[tex] \frac{1}{3} (6x+24)-20 \ \textless \ - \frac{1}{2} (6x-36)[/tex]
First, use the distributive property to simplify both sides of the equation.
[tex]2x+8-20\ \textless \ -3x+18[/tex]
Now, on the left side of the inequality, combine like terms.
[tex]2x-12\ \textless \ -3x+18[/tex]
Add 12 to both sides.
[tex]2x\ \textless \ -3x+30[/tex]
Add 3x to both sides.
[tex]5x\ \textless \ 30[/tex]
Divide 5 from both sides.
[tex]x\ \textless \ 6[/tex]
Therefore, the solution to the inequality is anything less than 6, or x < 6. Hope this helped!
