Respuesta :
15 d+3 b= 150 .........................(1)
5 d+6 b=120.............................(2)
From the first equation d=6 b=20
From the second equation it is d= 6 b= 20
5 d+6 b=120.............................(2)
From the first equation d=6 b=20
From the second equation it is d= 6 b= 20
Answer: a)[tex]6d=150-20b[/tex]
b) [tex]d=\frac{150-20b}{6}[/tex]
c)[tex]b=\frac{150-6d}{20}[/tex]
Step-by-step explanation:
Let d be the number of packages of hot dogs and b be the number of packages of hamburgers.
a)If the cost of a package of hot dogs is $6 and cost of a package of hamburger is $20, the required equation will be
[tex]6d+20b=150[/tex]
b) To solve for d, we subtract 20b from both sides, we get
[tex]6d=150-20b[/tex]
Now, divide 6 from both sides, we get
[tex]d=\frac{150-20b}{6}[/tex]
c) To solve for b, we subtract 6d from both sides, we get
[tex]20b=150-6d[/tex]
Now, divide 20 from both sides, we get
[tex]b=\frac{150-6d}{20}[/tex]