The length of a rectangle is 7 more than the width the area is 744 square centimeters find length and width of rectangle

Respuesta :

Answer:

[tex]l=31\ cm\\\\w=24\ cm[/tex]

Step-by-step explanation:

The formula that is used to calculate the area of a rectangle is:

[tex]A=lw[/tex]

Where "l" is the lenght and "w" is the width.

You know that the area of that rectangle is:

[tex]A=744\ cm^2[/tex]

And, according to the exercise, its lenght is 7 more than its width; then:

[tex]l=w+7[/tex]

Then, you can make the corresponding substitution into the formula [tex]A=lw[/tex]:

 [tex]744=(w+7)w[/tex]

Simplify:

[tex]744=w^2+7w\\\\w^2+7w-744=0[/tex]

Factor the equation. Find two numbers whose sum is 7 and whose product is -744. These are 31 and -24.

Then, you get:

[tex](w-24)(w+31)=0\\\\w_1=24\\\\w_2=-31[/tex]

The width of the rectangle is the positive value:

[tex]w=24\ cm[/tex]

Then, the lenght is:

[tex]l=24+7\\\\l=31\ cm[/tex]