Answer: 69.32 m
Step-by-step explanation:
Since, slant height of the square right pyramid, [tex]s^2=\sqrt{h^2+(1/4) a^2}[/tex]
where,
h = height of the pyramid
a= side of the square
And, here h= 62 m and a= 62 m
Therefore, [tex]s^2=\sqrt{62^2+(1/4) 62^2}[/tex]
⇒[tex]s^2=\sqrt{3844+961}[/tex]
⇒[tex]s^2=\sqrt{4805}[/tex]
⇒s=69.3181073025≈ 69.32 m
Thus, the height of triangular face = 69.32 ( approx)
