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In a dog show, there will be a gold, a silver, and a bronze medal awarded. there are 5 finalists. in how many different ways can the 3 medals be awarded?

Respuesta :

toporc
The number of permutations of 5 finalists taken 3 at a time is:
[tex]\frac{5!}{(5-3)!}=60[/tex]
The answer is 60 ways.
JeanaShupp

Answer:The number of different ways can the 3 medals be awarded=20.


Step-by-step explanation:

Given: In a dog show, there will be a gold, a silver, and a bronze medal awarded. there are 5 finalists.

By using permutation,

Number of different ways can the 3 medals be awarded=

[tex]^5P_3=\frac{5!}{(5-3)!}\\=\frac{5\times4\times3!}{3!}\\=5\times4=20[/tex]

Therefore, the number of different ways can the 3 medals be awarded=20.

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