contestada

What is an equation in slope-intercept form for the line that passes through the points (1,-3) and (3,1)?
A. y=3x+1
B. y=x-3
C. y=2x+5
D.y=2x-5

Respuesta :

MrGumby

The correct answer is D) y = 2x - 5

To find the equation of the line, start by finding the slope. You can do this by using the slope formula below.

m(slope) = (y2 - y1)/(x2 - x1)

m = (1 - -3)/(3 - 1)

m = 4/2

m = 2

Now that we have the slope, we can use it along with either point in point-slope form to get the equation.

y - y1 = m(x - x1)

y - 1 = 2(x - 3)

y - 1 = 2x - 6

y = 2x - 5

MrRoyal

The linear equation in slope intercept form is (d) [tex]y = 2x -5[/tex]

The points are given as: (1,-3) and (3,1)

Start by calculating the slope (m) of the points

[tex]m = \frac{y_2 - y_1}{x_2 - x_1}[/tex]

So, we have:

[tex]m = \frac{1--3}{3-1}[/tex]

[tex]m = \frac{4}{2}[/tex]

Divide

[tex]m = 2[/tex]

The line equation in slope intercept is then calculated using:

[tex]y = m(x - x_1) + y_1[/tex]

So, we have:

[tex]y = 2(x - 1) -3[/tex]

Open brackets

[tex]y = 2x - 2 -3[/tex]

Subtract 3 from -2

[tex]y = 2x -5[/tex]

Hence, the equation in slope intercept form is (d) [tex]y = 2x -5[/tex]

Read more about linear functions at:

https://brainly.com/question/1884491

Otras preguntas