What is the range of the function y=3 square root x+8

Answer with explanation:
⇒Range of function in two variables ,that contains variables x,and y are those values of y, for which x is defined.
For example ,consider the linear function , y=x
the set of values that ,x can take for which y is defined called Domain of the function.x∈R
And, the set of values that ,y can take for which x is defined called Range of the function.y∈R
The given function is
[tex]y=(x+8)^{\frac{1}{3}}[/tex]
Taking cube on both sides
[tex]y^3=x+8\\\\x=y^3-8[/tex]
→x is defined for all real values of y ,means for all real values of y,we are getting real values of x.So Range of the given function is ,y∈R.
Option A:→ -∞≤y≤∞