AD , BD , and CD are angle bisectors of the sides of △ABC . BE=12 m and BD=20 m.
What is DG ?

The answer is 16
And also , can people please stop posting did you get the answer yet, just so you could get the points. They only take two answers, and that's a waste of somebody who could've answered or helped.
Answer:
DG=16 m
Step-by-step explanation:
Given: AD, BD and Cd are the angle bisectors of the sides of ΔABC and B=12m and BD=20m.
To find: The value of DG.
Solution: It is given that AD, BD and Cd are the angle bisectors of the sides of ΔABC and B=12m and BD=20m, then from the ΔBED, we have
[tex](BD)^{2}=(BE)^{2}+(ED)^{2}[/tex]
Substituting the given values, we have
[tex](20)^2=(12)^2+(ED)^2[/tex]
[tex]400=144=(ED)^2[/tex]
[tex]400-144=(ED)^2[/tex]
[tex]256=(ED)^2[/tex]
[tex]16 m=ED[/tex]
Thus, the value of ED is 16m.
Now, we know that the distance from the mid points of the sides of the given triangle to the circumcenter D are equal, thus
ED=DG
ED=DG=16
Therefore, the value of DG is 16m.