Equation in point−slope form of the line passing through (2, 2) and (4, 8) is [tex]y-2 = 3(x-2)[/tex].
The point-slope form is used to find the equation of the straight line which is inclined at a given angle to the x-axis and passes through a given point.
Given
[tex](x_{1},y_{1}) = (2, 2)\\(x_{2} ,y_{2}) =(4,8)[/tex]
Point-slope form of the line
[tex]y-y_{1}=m(x-x_{1})[/tex]............(1)
Slope m = [tex]\frac{y_{2} -y_{1} }{x_{2} -x_{1}}[/tex]
m = [tex]\frac{8-2}{4-2}[/tex]
m = 3
Substituting m value in equation 1
[tex]y-2 = 3(x-2)[/tex]
Hence, equation in point−slope form of the line passing through (2, 2) and (4, 8) is [tex]y-2 = 3(x-2)[/tex].
Find out more information about point−slope form here
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