Respuesta :
Answer:
vertex is [tex](\frac{-1}{3}, \frac{-4}{3})[/tex]
Step-by-step explanation:
f(x) = 3x^2 - 2x - 1
Given equation is in the form of f(x) = ax^2 + bx+c
a=3 , b=-2 , c=-1
To find x coordinate of vertex we use formula x= -b/2a
[tex]x=\frac{-(-2)}{2(3)} = \frac{-1}{3}[/tex]
To find y coordinate of vertex plug in -1/3 in the place of x in f(X)
f(x) = 3x^2 - 2x - 1
[tex]f(\frac{-1}{3})= 3(\frac{-1}{3})^2 -2(\frac{-1}{3})-1= \frac{-4}{3}[/tex]
So vertex is [tex](\frac{-1}{3}, \frac{-4}{3})[/tex]
