In the diagram below P is circumscribed about quadrilateral ABCD? What is the value of X? PLS HELP

Answer:
[tex]x=80\°[/tex]
Step-by-step explanation:
we know that
If the quadrilateral is inscribed in a circle then the sum of its opposite angles is equal to [tex]180\°[/tex]
In this problem
m∠B and m∠D are opposite angles
so
m∠B + m∠D=[tex]180\°[/tex]
we have
m∠B=[tex]100\°[/tex]
solve for m∠D
m∠B=[tex]180\°-100\°=80\°[/tex]
[tex]x=80\°[/tex]
The value of [tex]x^{0}[/tex] is [tex]80^{0}[/tex].
An inscribed quadrilateral is any four sided figure whose vertices all lie on a circle. (The sides are therefore chords in the circle!) This conjecture give a relation between the opposite angles of such a quadrilateral. It says that these opposite angles are in fact supplements for each other.
According to the question
Quadrilateral is inscribed in a circle
If the quadrilateral is inscribed in a circle then the sum of its opposite angles is equal to [tex]180^{0}[/tex].
< B + < D = [tex]180^{0}[/tex]
We have < B = [tex]100^{0}[/tex]
[tex]100^{0}[/tex] + [tex]x^{0}[/tex] = [tex]180^{0}[/tex]
[tex]x^{0}[/tex] = [tex]180^{0}-100^{0}[/tex]
[tex]x^{0}[/tex] = [tex]80^{0}[/tex]
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