Respuesta :

Answer:

[tex]x=80\°[/tex]

Step-by-step explanation:

we know that

If the quadrilateral is inscribed in a circle then the sum of its opposite angles is  equal to [tex]180\°[/tex]

In this problem

m∠B and m∠D are opposite angles

so

m∠B + m∠D=[tex]180\°[/tex]

we have

m∠B=[tex]100\°[/tex]

solve for m∠D

m∠B=[tex]180\°-100\°=80\°[/tex]

[tex]x=80\°[/tex]

The value of  [tex]x^{0}[/tex]  is  [tex]80^{0}[/tex].

What is meant by quadrilateral is inscribed in a circle?

An inscribed quadrilateral is any four sided figure whose vertices all lie on a circle. (The sides are therefore chords in the circle!) This conjecture give a relation between the opposite angles of such a quadrilateral. It says that these opposite angles are in fact supplements for each other.

According to the question

Quadrilateral is inscribed in a circle

If the quadrilateral is inscribed in a circle then the sum of its opposite angles is  equal to [tex]180^{0}[/tex].

< B + < D =  [tex]180^{0}[/tex]

We have < B = [tex]100^{0}[/tex]

[tex]100^{0}[/tex] + [tex]x^{0}[/tex] =  [tex]180^{0}[/tex]

[tex]x^{0}[/tex]  = [tex]180^{0}-100^{0}[/tex]

[tex]x^{0}[/tex]  = [tex]80^{0}[/tex]

Find out more information about quadrilateral is inscribed in a circle here

https://brainly.com/question/9177423

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