Respuesta :

The expression is [tex]5y^2+3y+5+3y^2-5-3y-8y^2[/tex].

Collecting the constants, the first degree, and second degree terms together we have:

[tex](5-5)+(3y-3y)+(5y^2+3y^2-8y^2)=0+0+0=0[/tex].

Answer: 0

Answer:

[tex] \rm = {5y}^{2} + 3y + 5 + {3y}^{2} - 5 - 3y - {8y}^{2} [/tex]

[tex] \rm = 5 {y}^{2} + {3y}^{2} - {8y}^{2} + 3y - 3y + 5 - 5[/tex]

[tex] = 0[/tex]