Respuesta :
I think this is what u need.
1.Cd(NO3)2 + 2NH4Cl -> CdCl2 + 2NO3NH4
2.H3PO4(aq) + 3Ca(OH)2(aq) -> Ca3(PO4)2(aq) + 6H2O
1.Cd(NO3)2 + 2NH4Cl -> CdCl2 + 2NO3NH4
2.H3PO4(aq) + 3Ca(OH)2(aq) -> Ca3(PO4)2(aq) + 6H2O
Explanation:
Question 1.
The products in this chemical reaction are; CdCl2 and NH4NO3.
So we have;
Cd(NO₃)₂ + NH₄Cl ---> CdCl₂ + NH₄NO₃
The reaction is not balanced because we have unequal number of atoms of elements in both sides of the equation.
Upon balancing, we now have;
Cd(NO₃)₂ + 2NH₄Cl ---> CdCl₂ + 2NH₄NO₃
Question 2.
To write a net ionic equation:
- Write the balanced molecular equation.
2H₃PO₄(aq) + 3Ca(OH)₂(aq) ---> Ca₃ (PO₄)₂(aq) + 6H₂O(l)
- Write the balanced complete ionic equation.
6H+(aq] + 2PO³⁻₄(aq] + 3Ca²⁺(aq] + 6OH⁻(aq] → 3Ca²⁺(aq] + 2PO³⁻₄(aq] + 6H₂O(l]
Cross out the spectator ions that are present and Write the "leftovers" as the net ionic equation.
You can recognize spectator ions by looking for ions that are present on both sides of the equation. They will always have the same exact formula, charge, and physical state. They will also be present in exactly the same number on both sides of the equation.
6H⁺(aq] + 6OH⁻(aq] --> 6H₂O(l]