Respuesta :

Kalahira
ideal gas law is: PV = nRT P = pressure (torr) = 889 torr V = volume (Liters) = 11.8 L n = moles of gas = 0.444 mol R = gas constant = 62.4 (L * torr / mol * k) solve for T (in kelvin) T = PV/nR T = (889*11.8)/(.444*62.4) T = 378.6 K convert to C (subtract 273) T = 105.6 deg C

Answer: [tex]106^0C[/tex]

Explanation: IDEAL GAS LAW

[tex]PV=nRT[/tex]

where,

P = pressure of the gas  = 889 torr = 1.17 atm    (1 torr=0.0013atm)

V = volume of the gas  = 11.8 L

T = temperature of the gas  = ? K

n = number of moles of gas  = 0.444

R = Gas constant = 0.0821 Latm/moleK

[tex]1.17\times 11.8=0.444\times 0.0821\times T[/tex]

[tex]T=379K[/tex]

[tex]T=(379-273)^0C=106^0C[/tex]

Thus temperature of gas is [tex]106^0C[/tex]

Otras preguntas