If the child pulls with a force of 19 n for 15.0 m , and the handle of the wagon is inclined at an angle of 25 ∘ above the horizontal, how much work does the child do on the wagon?
The solution for this problem is we will be using the formula for work which is: Work = Fs, where F is the component of the force in the direction of motion Horizontal component of force = F = (19 N)(cos 25) = (19)(0.906) Fs = (190)(0.906) = 172.14 J
