Consider the exothermic reaction 4nh3(g)+5o2(g)→4no(g)+6h2o(g) calculate the standard heat of reaction, or δh∘rxn, for this reaction using the given data. also consider that the standard enthalpy of the formation of elements in their pure form is considered to be zero.

The first thing you need to know about this problem is that delta total = delta Hf products - delta Hf reactants.
Delta total = (4*NO + 6*H2O) - (5*O2 + 4*NH3)
Delta total = [(4*91.3 kJ/mol) + (6*-241.8 kJ/mol.) - (5*0 kJ/mol.) + (4*-45.9 kJ/mol.)
Products= 4*(365.2)+(-1450.8)=-1085.6 kJ
Reactants=4*(-45.9) + 5*(0)= -183.6 kJ
Delta Rxn= (-1085.6 kJ) - (-183.6 kJ) =-902.0 kJ

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nikitarahangdaleVT nikitarahangdaleVT · Answer 2 · 2022-05-03T09:04:46+02:00

The standard heat of reaction of the given exothermic reaction between ammonia & oxygen gas is -905.8 kJ/mol.

How do we calculate heat of reaction?

Heat of any chemical reaction will be calculated as the difference of the heat of reactants from the heat of reactants.

Heat of formation of NH₃(g) = -46 kJ/mol

Heat of formation of O₂(g) = 0 kJ/mol

Heat of formation of NO(g) = 90.25 kJ/mol

Heat of formation of H₂O(g) = -241.8 kJ/mol

Heat of the reaction according to the given chemical equation will be calculated as:
ΔHrxn = (4×NO + 6×H₂O) - (5×O₂ + 4×NH₃)

ΔHrxn = [4(90.25) + 6(-241.8)] - [5(0) + 4(-46)]

ΔHrxn = 361 - 1,450.8 + 184

ΔHrxn = -905.8 kJ/mol

Hence heat of reaction is -905.8 kJ/mol.

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