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Jack is selling tickets to an event. attendees can either buy a general admission ticket or a vip ticket. the general admission tickets are $60 in the vip tickets are $90. he doesn't know how many of each type he has sold, but he knows he sold a total of 29 tickets and made $2100.

Respuesta :

x+y=29
60x+90y=2100

substitute the value of x as (29-y) in the second equation 
60(29-y) + 90y =2100
30y = 2100-1740=360
y=12 so x=17
so 17  general tickets were sold and 12 vip tickets were sold.
Ondinne

Answer:

Jack sold 17 admission tickets and 12 vip tickets.

Step-by-step explanation:

1. Let´s name the variables as:

x=number of admission tickets

y=number of vip tickets

2. As the problem says Jack sold a total of 29 tickets, it can be expressed as:

[tex]x+y=29[/tex] (Eq.1)

3. As the general admission tickets are $60, the vip tickets are $90 and he made $2100, it can be expressed as:

[tex]60x+90y=2100[/tex] (Eq.2)

4. Solve for x on the Eq.1:

[tex]x=29-y[/tex] (Eq.3)

5. Replace Eq.3 in Eq.2:

[tex]60(29-y)+90y=2100\\1740-60y+90y=2100\\-60y+90y=2100-1740\\30y=2100-1740\\30y=360\\y=\frac{360}{30}\\y=12[/tex]

6. Replace the value of y in Eq.3:

[tex]x=29-12\\x=17[/tex]

Therefore Jack sold 17 admission tickets and 12 vip tickets.

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