Answer:
The moment of inertia of the fan is 2.60 kg-m²
Explanation:
Given that,
Angular speed = 2.20 rad/s
Torque = 0.225 N-m
Time = 25.5 sec
We need to calculate the moment of inertia of the fan
Using formula of torque
[tex]\tau=I\times \alpha[/tex]
We know that,
The angular velocity is
[tex]\Delta \omega=\alpha t[/tex]
[tex]\alpha=\dfrac{\Delta\omega}{t}[/tex]
Put the value of [tex]\alpha[/tex] in to the formula of torque
[tex]\tau=I\times\times\dfrac{\Delta\omega}{t}[/tex]
[tex]I=\dfrac{\tau\times t}{\Delta\omega}[/tex]
Put the value into the formula
[tex]I=\dfrac{0.225\times25.5}{2.20}[/tex]
[tex]I=2.60\ kg-m^2[/tex]
Hence, The moment of inertia of the fan is 2.60 kg-m²
