Answer:
[tex]8<\sqrt{66}<9[/tex]
Step-by-step explanation:
We are asked to find two consecutive whole numbers that square root 66 lies between.
We know that square root of 64 is a whole number that is 8 and square root of 81 is also a whole number that is 9.
[tex]\sqrt{64}<\sqrt{66}<\sqrt{81}[/tex]
[tex]\sqrt{8^2}<\sqrt{66}<\sqrt{9^2}[/tex]
[tex]8<\sqrt{66}<9[/tex]
Therefore, square root of 66 lies between 8 and 9.
