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4. A big league hitter attacks a fastball! The ball has a mass of 0.16 kg. It is pitched at 38 m/s. After the player hits the ball, it is now traveling 44 m/s in the opposite direction. The impact lasted 0.002 seconds. How big of a force did the ballplayer put on that ball?

Respuesta :

Edufirst
Use conservation of linear momentum (p) and impulse (I)

Formulas:

p = m*v

I = Δp = f * t

1) Linear momentum of the ball before being hitted by the player:

p = m * v = 0.16 kg * ( - 38 m/s) = - 6.08 N*s

2) linear momentum of the ball after being hitted:

p = m * v = 0.16 kg * (44 m/s) = + 7.04 N*s

3) Change of linear momentum

Δp = + 7.04 n*s - ( -6.08 N*s) = 13.12 N*s

4) Impulse

I = Δp = f * t => f = Δp * t = 13.12 N*s / 0.002 s = 6,560 N

Answer: 6,560 N

the answer is 6,560

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