Solution:
Two polygons are said to be similar if ratio of their corresponding sides are same and their interior angles are congruent.
Consider Polygon 1 and Polygon 4
AB= DE= 8 units, AE= 6 units,
PT=QR= 4 Units, PQ= 3 Units
[tex]\frac{AB}{PT}=\frac{DE}{QR}=\frac{AE}{PQ}=\frac{BC}{SR}=\frac{CD}{TS}[/tex]
So, Polygon 1 ≅ Polygon 4
Now, Consider Polygon 2 and Polygon 3
LM=KO=6 units, LK=4 units
GF= 4 units, GH=FJ =4 Units
As you can see that polygon 2 and polygon 4 doesn't have corresponding proportional sides i.e [tex]\frac{6}{4}\neq \frac{4}{4}[/tex].
So, Polygon 2 is not congruent to Polygon 4.
