shelbycg02
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The number of pollinated flowers as a function of time in days can be represented by the function. f(x)=(3)x2 What is the average increase in the number of flowers pollinated per day between days 4 and 10?
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W0lf93

So in this case f(x) is number of pollinated flowers and x is the days. First you will need to determine the number of flowers pollinated at days 4 and 10 and the days in between.  
f(4)= 3(4^2)= 3*16 = 48  
f(5)= 3(5^2)= 3*25 =75  
f(6)= 3(6^2)=3*36=108  
f(7)= 3(7^2)=3*49=147  
f(8)= 3(8^2)=3*64=192  
f(9)= 3(9^2)= 3*81=243  
f(10)= 3(10^2)=3*100=300    
Now we need to find the average increase, so that will be the average of the differences between days  
[(75-48)+(108-75)+(147-108)+(192-147)+(243-192)+(300-243)]/6  
=(27+33+39+45+51+57)/6=42

Answer:

This is the correct answer! Sorry I am late also, but hope this helps other students! Also sorry for horrible handwriting.. lol! Have a nice day! And this really helpful for k12 users.

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