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Triangle ABC is such that AB = 3cm , BC = 4cm , angle ABC = 120 and BAC = theta : Write down in terms of theta , and expression for angle ACB ( why is this (60-theta) and not (120-theta)? Next question asks for using the sine rule (or otherwise) show that tan theta = 2sqrt3 /(5) A diagram would be pretty cool guys

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underV
1)inside the triangule is 180º .There are 3 angules, one with 120º, theta and
angle ACB, lets call it x.

x + theta + 120 = 180
x + theta= 180-120
x + theta= 60
x= 60- theta
angle ACB= 60- theta

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