The solution set of the equation x² + 3x - 4 = 6 is [tex]x = 5[/tex] or [tex]x = - 2[/tex]
Given the equation :
[tex]x^{2} + 3x - 4 = 6\\x^{2} + 3x - 4 - 6 = 0\\x^{2} + 3x - 10 = 0\\[/tex]
Two values whose sum gives 3 and product gives - 10
The values are 5 and - 2
[tex]x^{2} + 5x - 2x - 10 = 0\\\\x(x + 5) - 2(x + 5) = 0\\\\(x + 5) = 0\\\\(x - 2) = 0\\\\x = - 5 \\\\or\\\\ x = 2[/tex]
Hence, the solution set of the equation x² + 3x - 4 = 6 is x = - 5 or x = 2
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