PLEASE HELP!:)
The coordinates of the vertices of a polygon are (−5, 1) , (−1, 3) , (2, 3) , (2, −2) , and (−3, −1) .

What is the perimeter of the polygon?


Enter your answer as a decimal, rounded to the nearest tenth of a unit, in the box.

units

Respuesta :

The perimeter would be 14.572, rounded to the nearest tenth would be 14.6. Hope this helps!

Answer:

20.4 units

Step-by-step explanation:

The coordinates of the vertices of a polygon are (−5, 1) , (−1, 3) , (2, 3) , (2, −2) , and (−3, −1) .

What is the perimeter of the polygon?

Enter your answer as a decimal, rounded to the nearest tenth of a unit, in the box.

units

A=(−5, 1) ,

B= (−1, 3) ,

C=(2, 3) ,

D= (2, −2)

E=,(−3, −1) .

there are about five points

AB,BC,CD,DE,EA

to find the distance between two point s we use the formula

d=[tex]\sqrt{(x_{2} -x_{1})^2+(y_{2}} -y_{1} )^2[/tex]

for AB=d=[tex]\sqrt{(x_{2} -x_{1})^2+(y_{2}} -y_{1} )^2[/tex]

(-1-(-5)^2+(3-1)^2=16+4=20

[tex]\sqrt{20}[/tex]

AB=4.47

BC=(2--1)^2+(3-3)^2=9

[tex]\sqrt{9}[/tex]

BC=3

CD=(2-2)^2+(-2-3)^2=25

CD=[tex]\sqrt{25}[/tex]

CD=5

DE=(-3-2)^2+(-1--2)^2

DE=[tex]\sqrt{26}[/tex]

DE=5.09

EA=(-5--3)^2+(2)^2

4+4=8

EA=[tex]\sqrt{8}[/tex]

EA=2.82

The perimeter is the length of the sides

AB+BC+CD+DE+EA

4.47+3+5+5.09+2.82

20.38=20.4

What is the perimeter of the polygon?

20.4 units