Nicky156
contestada

I will give the BRAINLIEST for whoever is right.

The total bear population in a certain area is represented by the function P=120(1.016)^t , where t is time in years.

How could this function be rewritten to identify the weekly growth rate of the population?

What is the weekly growth rate?



Drag and drop the choices into the boxes to correctly complete the table. If a value does not match, do not drag it to the table.

Function: ???


Weekly Growth Rate: ???



Options:

P=120(1.016^1/52)^52t || P=120(1.016)^t/52 || P=120(1.016^52)^t || 0.03% || 0.019% || 1.0003%

Respuesta :

RickSanchez42
r= .016*100=1.6
R= 1.6%

R=1.6 over 52*100= 0.03076923077 per week
Growth= 0.03
function= P=120(1.016^1/52)^52t
Hope this helps! ^-^

mathjohndough

The population growth function is [tex]P=120(1.016)^t.[/tex] To work out the weekly growth rate, we assume that there are 52 weeks per year.

We have to divide [tex]t[/tex] by 52 to get the weekly growth rate.

To identify the weekly growth rate we have to write the function as,

[tex]P=120(1.016)^\frac{t}{52}.[/tex]

To get the weekly growth rate, we have to first simplify the function using the laws of indices namely,[tex]a^{ab}=(a^a)^b[/tex] .

[tex]P=120(1.016)^{\frac{1}{52}t }=120(1.016^\frac{1}{52})^t=120(1.0003)^t=120(1+0.0003)^t.[/tex]

From the equation above we can easily read the growth rate as 0.0003 or [tex]0.03\%[/tex]


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