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A uniform solid disk of mass m = 2.91 kg and radius r = 0.200 m rotates about a fixed axis perpendicular to its face with angular frequency 6.08 rad/s. (a) calculate the magnitude of the angular momentum of the disk when the axis of rotation passes through its center of mass.

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shinmin
The answer for this problem is:
It is just a simple application of L = I w with w = 6.08 rad/m 
Case 1: Center-of-mass case 
I = 1/2 MR Sq.: giving 
L= (1/2 M R Sq) (w) =1/2 x2.91 x0.2x 0.2 x 6.08
=0.35 kg m Sq .Ans 1 is the magnitude for this problem.

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