Respuesta :

minimum 4
first quartile 9
median 9 & 18
third quartile 18
maximum 20

Answer:

Minimum = 4

First quartile = 6.5

Median = 13.5

Third quartile = 19

Maximum = 20

Step-by-step explanation:

1. Order the data set from the smallest to the largest number:

4  4  9  9  18  18  20  20

2. Find the minimum:

The minimum of the data set is the smallest number

Minimum = 4

3. Find the maximum:

The maximum of the data set is the largest number

Maximum = 20

4. Find the median:

As the data set has an even number of data, the median is the average between 9 and 18, that are the two data in the middle:

Median = [tex]\frac{9+18}{2}[/tex]

Median = 13.5

5. Find the first quartile:

The median divide the data set between two groups:

4  4  9  9     Median=13.5     18  18  20  20

The first quartile is the average of the two data in the middle of the first group:

4  4  9  9

First quartile = [tex]\frac{4+9}{2}[/tex]

First quartile = 6.5

6. Find the third quartile:

The third quartile is the average of the two data in the middel of the second group:

18  18  20  20

Third quartile = [tex]\frac{18+20}{2}[/tex]

Third quartile = 19