Erin writes the set of ordered pairs below. The set represents a function.

{(3, –3), (5, 0), (–1, 4), (–6, 7)}

Erin claims that she can add any point to the set and have the set still represent a function.

Which of the following points can be used to show that Erin's claim is incorrect? Select three that apply.
A.(–6, 1)
B.(–1, 9)
C.(0, 5)
D.(1, 7)
E.(3, –2)


Respuesta :

Point A shows that she is incorrect.
With functions, you can perform the "straight line test through each point. If the line goes through both points, you know it's not a function.
If we plotted point A, it'd fail the straight line test because the given point (-6, 7) already has -6 as an x value.
Hope this helps!

The following points can be used to show that Erin's claim is incorrect is given by:

  • Option A.(–6, 1)
  • Option B.(-1, 9)
  • Option E.(3,-2)

What is a function?

There are two sets of values. When we connect first set's values with other set, it is called mapping one set's value to other set.  The function's set is then written as {(x,y)} form, where x is input value, and y is output of the function in consideration. All type of mappings are called relations.

Such relations which are such that each element of the first set(also called input set or domain) is mapped to only one value of the other set(called codomain, and if all values are occupied, then called range or output set), then such relation is called function.

So, for a mapping to be function, we need each input to be mapped to only one output.

Since it is given that {(3, –3), (5, 0), (–1, 4), (–6, 7)} are set of points valid for considered function, so if one input maps to two outputs, then it won't remain a set anymore.

Thus, Option A, Option B, Option E all are such that they provide one more output(different than the output that is already used for that input) for already available input, thus, making that set of values not being a function. Like, for example, option A is (-6,1) but in the set given, -6 maps to 7, so if (-6,1) is added to the existing set of pair of input output, we see that -6 now maps to two different outputs 1 and 7, so making this relation not being a function.

Thus, he following points can be used to show that Erin's claim is incorrect is given by:

  • Option A.(–6, 1)
  • Option B.(-1, 9)
  • Option E.(3,-2)

Learn more about functions here:

https://brainly.com/question/13395697