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A big ship drops its anchor. E(t) models the anchor's elevation relative to the water's surface (in meters) as a function of time t (in seconds). E(t)=−2.4t+75 How far does the anchor drop every 5 seconds?

Respuesta :

Plug in 5 for t, while ignoring the +75.
[tex]2.4(5) = 12[/tex]
Therefore, the anchor drops 12 m. every 5 seconds

Answer:

The anchor drops 12 meters every 5 seconds, assuming that it moves constantly.

Step-by-step explanation:

The given function is

[tex]E(t)= -2.4t+75[/tex]

Where E(t) models the anchor's elevations in relation to the water's surface. Notice that the function depends on the time.

Now, to find how far does the anchor drop every 5 seconds, we just need to replace [tex]t=5[/tex]

[tex]E(5)= -2.4(5)+75=-12+75=63[/tex]

However, we just need the rate per second, which doesn't include the initial condition of 75 meters, because that's would  mean we are gonna give the total meters.

[tex]2.4(5)=12[/tex]

Therefore, the anchor drops 12 meters every 5 seconds, assuming that it moves constantly.

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