[tex]\bf ~~~~~~\textit{parabola vertex form}
\\\\
\begin{array}{llll}
\boxed{y=a(x-{{ h}})^2+{{ k}}}\\\\
x=a(y-{{ k}})^2+{{ h}}
\end{array}
\qquad\qquad
vertex~~(\stackrel{}{{{ h}}},\stackrel{}{{{ k}}})\\\\
-------------------------------\\\\
f(x)=6x^2\implies f(x)=6(x-\stackrel{h}{0})^2\stackrel{k}{+0}
\\\\\\
now\qquad
\begin{cases}
h=2\\
k=5
\end{cases}\implies f(x)=6(x-2)^2+5
\\\\\\
f(x)=6(x^2-2x+2^2)+5\implies f(x)=6x^2-12x+24+5
\\\\\\
f(x)=6x^2-12x+29[/tex]
